判断日期是否为周六周日,BigDecimal比较大小
判断日期是否为周六周日,BigDecimal比较大小
代码语言:javascript代码运行次数:0运行复制package com.example.core.mydemo.date;
import java.math.BigDecimal;
import java.time.DayOfWeek;
import java.time.LocalDateTime;
/**
* today=6
* today2=SATURDAY
* 周末
* a+b=300
* 111
*/
public class DateTest {
public static void main(String[] args) {
// LocalDateTime dateTime = LocalDateTime.now();
LocalDateTime dateTime = LocalDateTime.of(2023,4,8,0,0,0);
DayOfWeek week = dateTime.getDayOfWeek();
System.out.println("today=" + week.getValue());
System.out.println("today2=" + week);
if(week==DayOfWeek.SATURDAY || week==DayOfWeek.SUNDAY){
System.out.println("周末");
}else {
System.out.println("工作日");
}
Integer a = new Integer(100);
Integer b = new Integer(200);
System.out.println("a+b="+(a+b));
/**
* 如果price1为null或0,则取price2
*/
BigDecimal price1 = new BigDecimal(0);;
BigDecimal price2 = new BigDecimal(200);
if(price1 == null && price2 != null){
price1 = price2;
System.out.println("price1=" + price1);
}
if(price1pareTo(new BigDecimal(0)) == 0 && price2pareTo(new BigDecimal(0)) != 0){
System.out.println("111");
}else {
System.out.println("222");
}
}
}
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